حلول الأسئلة

السؤال

أوجد ناتج الضرب في كل مما يأتي، ثم أكتبه في أبسط صورة:

الحل

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

 

شاهد حلول جميع الاسئلة

حل أسئلة تدرب وحل المسائل

ضرب

تدريب

أوجد ناتج الضرب في كل مما يأتي، ثم أكتبه في أبسط صورة:

٩- right to left ١ over ٣ cross times ٢ ove

= right to left ٢ over �

١٠- right to left ١ over ٨ space cross times ٣ ove

= right to left ٣ over �

١١- right to left ٣ over ٤ cross times ٥ ove

= right to left ١٥ over

١٢- right to left ٢ over ٥ cross times ٣ ove

= right to left ٦ over �

١٣- right to left ٣ over ٤ cross times

= right to left ٣ over ٤ cross times ٢ over ١ equals space ٦ over ٤ equals space ٣ over ٢ space equals ١

١٤- right to left ٢ over ٣ cross times

= right to left ٢ over ٣ cross times ٤ over ١ equals ٨ over ٣ equals ٢ o

١٥- right to left ٥ over ٦ cross times ١٥ s

= right to left ٥ over ٦ cross times ١٥ over ١ space equals ٧٥ over ٦ equals space ١

١٦- right to left ٣ over ٨ cross times ١١ space s

= right to left ٣ over ٨ cross times ١١ over ١ equals ٣٣ over ٨ equals ١

١٧- right to left ٢ over ٣ cross times ١ ove

= right to left fraction numerator down diagonal strike ٢ over denominator ٣ end fraction cross times fraction numerator ١ over denominator down diagonal strike ٤ end fraction subscript left parenthesis ٢ right parenthesis end subscript space equals space ١

١٨- right to left ٣ over ٥ cross times ٥ ove

= right to left fraction numerator ٣ over denominator down diagonal strike ٥ end fraction cross times fraction numerator down diagonal strike ٥ over denominator ٧ end fraction space equals space ٣ o

١٩- right to left ٤ over ٩ cross times ٣ ove

= right to left fraction numerator down diagonal strike ٤ over denominator down diagonal strike ٩ end fraction subscript left parenthesis ٣ right parenthesis end subscript cross times fraction numerator down diagonal strike ٣ over denominator down diagonal strike ٨ end fraction subscript left parenthesis ٢ right parenthesis end subscript space equals space ١

٢٠- right to left ٢ over ٥ cross times ٥ ove

= right to left fraction numerator down diagonal strike ٢ over denominator down diagonal strike ٥ end fraction cross times fraction numerator down diagonal strike ٥ over denominator down diagonal strike ٦ end fraction subscript left parenthesis ٣ right parenthesis end subscript space equals space ١

جبر: إذا كانت أ = right to left ٣ over ، ب = right to left ١ over ، جـ = right to left ١ over ، فاحسب قيمة كل عبارة مما يأتي:

٢١- أ ب

= right to left ٣ over × right to left ١ over = right to left ٣ over �

٢٢- ب جـ

= right to left ١ over × right to left ١ over = K subscript b equals fraction numerator left square bracket HCO subscript 3 superscript minus right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket CO subscript 3 superscript 2 minus end superscript right square bracket end fraction

٢٣- K subscript b equals fraction numerator left square bracket straight C subscript 6 straight H subscript 13 NH subscript 3 superscript plus right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket straight C subscript 6 straight H subscript 13 NH subscript 2 right square bracket end fraction أ

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٢٤- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction جـ

= K subscript b equals fraction numerator left square bracket straight C subscript 6 straight H subscript 13 NH subscript 3 superscript plus right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket straight C subscript 6 straight H subscript 13 NH subscript 2 right square bracket end fraction × K subscript b equals fraction numerator left square bracket straight C subscript 6 straight H subscript 13 NH subscript 3 superscript plus right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket straight C subscript 6 straight H subscript 13 NH subscript 2 right square bracket end fraction = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٢٥- حيوانات: يمضي حيوان (الكسلان) K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction عمره تقريباً نائماً، فإذا كان يعيش حتى ٢٨ سنة، فأوجد عدد السنوات التي يمضيها نائماً.

عدد السنوات = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × ٢٨ = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction سنة.

٢٦- نفط: إذا كان الإنتاج اليومي لسلطنة عمان من النفط K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction من إنتاج المملكة العربية السعودية. فما إنتاج السلطنة، إذا كان إنتاج المملكة ٩ ملايين برميل يومياً؟

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × ٩٠٠٠٠٠٠ = ٢٧٠٠٠٠٠٠ برميل يومياً.

٢٧- القياس: تشكل المسافة بين مكة المكرمة والمدينة المنورة K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction المسافة وبين مكة المكرمة ونجران تقريباً. فإذا كانت المسافة بين مكة المكرمة ونجران ٩٠٠ كلم، فأوجد المسافة بين مكة المكرمة والمدينة المنورة.

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × ٩٠٠ = ٣٦٠ كلم

أوجد ناتج الضرب في كل مما يأتي، ثم اكتبه في أبسط صورة:

٢٨- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٢٩- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٣٠- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

الجبر: إذا كانت س = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction ، ص = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction ، ع = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction ، فاستعمل ترتيب العمليات لتجد قيمة كل عبارة مما يأتي:

٣١- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction س ع

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٣٢- س ص ع

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٣٣- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction س + ع

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٣٤- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction ص + K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fractionع

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction× K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction + K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٣٥- مساحة: تبلغ مساحة جامعة الملك عبد الله للعلوم والتقنية ٣٦ كلم٢ ،إذا كانت المباني السكنية والجامعية والمرافق المركزية تغطي K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction هذه المساحة، فأوجد مساحة هذا الجزء.

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × ٣٦ = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction كلم٢

٣٦- صحة: إذا كان متوسط عدد ضربات القلب لدى الإنسان ٧٢ مرة في الدقيقة، فأوجد K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction هذا العدد واكتبه في صورة عدد كسري.

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × ٧٢ = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٣٧- أداء العمرة: ذهب K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction موظفي شركة لأداء مناسك العمرة، فاشترى ٤ منهم هدايا عند عودتهم. فأي مما يأتي يمكن، يكون تقديراً معقولاً لعدد موظفي تلك الشركة: ١٨أم ٢٦ أم ٣٠ موظفاً؟ وضح إجابتك.

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × ١٨ = ٣ موظفين وهو غير معقول حيث من المسألة أن ٤ من المعتمرين اشتروا هدايا.

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × ٢٦ = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction غير معقول حيث لا يوجد K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction موظف.

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction× ٣٠ = ٥ موظفين، وهي الإجابة الصحيحة.

٣٨- أشجار: تمثل أشجار الحمضيات K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction من أشجار بستان. إذا علمت أن K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction أشجار الحمضيات ليمون، وأن العدد الكلي لأشجار البستان هو ٧٢٠ شجرة، فما عدد أشجار الليمون؟

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction× K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction × K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction= ١١٧ شجرة.

٣٩- مسألة مفتوحة: اعمل نموذجاً توضح من خلاله أن ناتج K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction يساوي K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

12

تبرير: أي الجملتين الآتيين صحيحة وأيهما خاطئة؟ أعط مثالاً مضاداً للجملة الخاطئة:

٤٠- ناتج ضرب عددين كسريين، كل منهما بين ٤ و٥ وكسر بين ٠ و١ ويكون أصغر من ٤

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fractionأصغر من ٤.

٤١- ناتج ضرب عددين كسريين، كل منهما بين ويقع بين ١٦ و٢٥.

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fractionيقع بين ١٦ و٢٥ إذن الإجابة صحيحة.

٤٢- الحس العددي: إذا كان أ، ب كسرين ناتج ضربهما K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction ، فأوجد ثلاث قيم ممكنة لكل من أ، ب.

بفرض أ = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction - K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction - K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

بفرض ب = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction - K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction - K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٤٣- تحد: هل ناتج ضرب كسرين، كل منهما أصغر من ١ يكون أيضاً من ١؟ فسر إجابتك.

نعم لأن ضرب س في كسر أصغر من ١ يعطي كسرا أصغر من س. لذا إذا كان س كسراً أصغر من ١، فإن الناتج يكون أصغر من ١.

٤٤- اكتب: تفسيراً، لماذا يكون K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction ؟

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

تدريب

٤٥- إذا كان الدواجن الموجودة في مزرعة هو دجاجاً وكان هذا الدجاج ديوكاً فأي مما يأتي يمثل الكسر الدال على عدد الديوك بالنسبة للمزرعة؟

أ. K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

ب. K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

جـ. K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

د. K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

٤٦- جمعية تطوعية عدد أعضائها ١٥٠ شخصاً، ونصف هذا العدد رجال، جمعية أخرى عددها ٩٠ شخصاً و K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction عدد هذه الجمعية رجال كم يزيد عدد الرجال في الجمعية الأولى على عدد الرجال في الجمعية الثانية؟

أ. ٣

ب. ١٨

جـ. ٢٧

د. ٧٢

مشاركة الدرس

السؤال

أوجد ناتج الضرب في كل مما يأتي، ثم أكتبه في أبسط صورة:

الحل

K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction = K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

 

حل أسئلة تدرب وحل المسائل

ضرب

تدريب

أوجد ناتج الضرب في كل مما يأتي، ثم أكتبه في أبسط صورة:

٩- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

١٠- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

١١- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

١٢- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

١٣- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

١٤- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

١٥- K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

= K subscript b equals fraction numerator left square bracket straight H subscript 2 SO subscript 4 right square bracket times left square bracket OH to the power of minus right square bracket over denominator left square bracket HSO subscript 4 superscript minus right square bracket end fraction

١٦- K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket NO subscript 2 superscript minus right square bracket over denominator left square bracket HNO subscript 2 right square bracket end fraction

= K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket NO subscript 2 superscript minus right square bracket over denominator left square bracket HNO subscript 2 right square bracket end fraction

١٧- K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket NO subscript 2 superscript minus right square bracket over denominator left square bracket HNO subscript 2 right square bracket end fraction

= K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket NO subscript 2 superscript minus right square bracket over denominator left square bracket HNO subscript 2 right square bracket end fraction

١٨- K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket NO subscript 2 superscript minus right square bracket over denominator left square bracket HNO subscript 2 right square bracket end fraction

= K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket NO subscript 2 superscript minus right square bracket over denominator left square bracket HNO subscript 2 right square bracket end fraction

١٩- K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket NO subscript 2 superscript minus right square bracket over denominator left square bracket HNO subscript 2 right square bracket end fraction

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٢٠- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

جبر: إذا كانت أ = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ، ب = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ، جـ = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ، فاحسب قيمة كل عبارة مما يأتي:

٢١- أ ب

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٢٢- ب جـ

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٢٣- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction أ

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٢٤- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction جـ

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٢٥- حيوانات: يمضي حيوان (الكسلان) text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction عمره تقريباً نائماً، فإذا كان يعيش حتى ٢٨ سنة، فأوجد عدد السنوات التي يمضيها نائماً.

عدد السنوات = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × ٢٨ = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction سنة.

٢٦- نفط: إذا كان الإنتاج اليومي لسلطنة عمان من النفط text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction من إنتاج المملكة العربية السعودية. فما إنتاج السلطنة، إذا كان إنتاج المملكة ٩ ملايين برميل يومياً؟

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × ٩٠٠٠٠٠٠ = ٢٧٠٠٠٠٠٠ برميل يومياً.

٢٧- القياس: تشكل المسافة بين مكة المكرمة والمدينة المنورة text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction المسافة وبين مكة المكرمة ونجران تقريباً. فإذا كانت المسافة بين مكة المكرمة ونجران ٩٠٠ كلم، فأوجد المسافة بين مكة المكرمة والمدينة المنورة.

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × ٩٠٠ = ٣٦٠ كلم

أوجد ناتج الضرب في كل مما يأتي، ثم اكتبه في أبسط صورة:

٢٨- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٢٩- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٣٠- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

الجبر: إذا كانت س = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ، ص = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ، ع = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ، فاستعمل ترتيب العمليات لتجد قيمة كل عبارة مما يأتي:

٣١- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction س ع

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٣٢- س ص ع

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٣٣- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction س + ع

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٣٤- text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ص + text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fractionع

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction× text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction + text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

= text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٣٥- مساحة: تبلغ مساحة جامعة الملك عبد الله للعلوم والتقنية ٣٦ كلم٢ ،إذا كانت المباني السكنية والجامعية والمرافق المركزية تغطي text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction هذه المساحة، فأوجد مساحة هذا الجزء.

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × ٣٦ = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction كلم٢

٣٦- صحة: إذا كان متوسط عدد ضربات القلب لدى الإنسان ٧٢ مرة في الدقيقة، فأوجد text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction هذا العدد واكتبه في صورة عدد كسري.

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × ٧٢ = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٣٧- أداء العمرة: ذهب text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction موظفي شركة لأداء مناسك العمرة، فاشترى ٤ منهم هدايا عند عودتهم. فأي مما يأتي يمكن، يكون تقديراً معقولاً لعدد موظفي تلك الشركة: ١٨أم ٢٦ أم ٣٠ موظفاً؟ وضح إجابتك.

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × ١٨ = ٣ موظفين وهو غير معقول حيث من المسألة أن ٤ من المعتمرين اشتروا هدايا.

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × ٢٦ = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction غير معقول حيث لا يوجد text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction موظف.

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction× ٣٠ = ٥ موظفين، وهي الإجابة الصحيحة.

٣٨- أشجار: تمثل أشجار الحمضيات text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction من أشجار بستان. إذا علمت أن text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction أشجار الحمضيات ليمون، وأن العدد الكلي لأشجار البستان هو ٧٢٠ شجرة، فما عدد أشجار الليمون؟

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction× text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction × text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction= ١١٧ شجرة.

٣٩- مسألة مفتوحة: اعمل نموذجاً توضح من خلاله أن ناتج text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction يساوي text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

12

تبرير: أي الجملتين الآتيين صحيحة وأيهما خاطئة؟ أعط مثالاً مضاداً للجملة الخاطئة:

٤٠- ناتج ضرب عددين كسريين، كل منهما بين ٤ و٥ وكسر بين ٠ و١ ويكون أصغر من ٤

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fractionأصغر من ٤.

٤١- ناتج ضرب عددين كسريين، كل منهما بين ويقع بين ١٦ و٢٥.

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fractionيقع بين ١٦ و٢٥ إذن الإجابة صحيحة.

٤٢- الحس العددي: إذا كان أ، ب كسرين ناتج ضربهما text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ، فأوجد ثلاث قيم ممكنة لكل من أ، ب.

بفرض أ = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction - text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction - text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

بفرض ب = text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction - text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction - text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction

٤٣- تحد: هل ناتج ضرب كسرين، كل منهما أصغر من ١ يكون أيضاً من ١؟ فسر إجابتك.

نعم لأن ضرب س في كسر أصغر من ١ يعطي كسرا أصغر من س. لذا إذا كان س كسراً أصغر من ١، فإن الناتج يكون أصغر من ١.

٤٤- اكتب: تفسيراً، لماذا يكون text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction ؟

text end text K subscript straight a equals fraction numerator left square bracket straight H subscript 3 straight O to the power of plus right square bracket left square bracket CIO subscript 2 to the power of minus right square bracket over denominator left square bracket HCIO subscript 2 right square bracket end fraction = K subscript a equals fraction numerator left square bracket AsO subscript 4 superscript 3 minus end superscript right square bracket times left square bracket straight H subscript 3 straight O to the power of plus right square bracket over denominator left square bracket HAsO subscript 4 superscript 2 minus end superscript right square bracket end fraction

تدريب

٤٥- إذا كان الدواجن الموجودة في مزرعة هو دجاجاً وكان هذا الدجاج ديوكاً فأي مما يأتي يمثل الكسر الدال على عدد الديوك بالنسبة للمزرعة؟

أ. K subscript a equals fraction numerator left square bracket AsO subscript 4 superscript 3 minus end superscript right square bracket times left square bracket straight H subscript 3 straight O to the power of plus right square bracket over denominator left square bracket HAsO subscript 4 superscript 2 minus end superscript right square bracket end fraction

ب. K subscript a equals fraction numerator left square bracket AsO subscript 4 superscript 3 minus end superscript right square bracket times left square bracket straight H subscript 3 straight O to the power of plus right square bracket over denominator left square bracket HAsO subscript 4 superscript 2 minus end superscript right square bracket end fraction

جـ. K subscript a equals fraction numerator left square bracket AsO subscript 4 superscript 3 minus end superscript right square bracket times left square bracket straight H subscript 3 straight O to the power of plus right square bracket over denominator left square bracket HAsO subscript 4 superscript 2 minus end superscript right square bracket end fraction

د. K subscript a equals fraction numerator left square bracket AsO subscript 4 superscript 3 minus end superscript right square bracket times left square bracket straight H subscript 3 straight O to the power of plus right square bracket over denominator left square bracket HAsO subscript 4 superscript 2 minus end superscript right square bracket end fraction

٤٦- جمعية تطوعية عدد أعضائها ١٥٠ شخصاً، ونصف هذا العدد رجال، جمعية أخرى عددها ٩٠ شخصاً و K subscript a equals fraction numerator left square bracket AsO subscript 4 superscript 3 minus end superscript right square bracket times left square bracket straight H subscript 3 straight O to the power of plus right square bracket over denominator left square bracket HAsO subscript 4 superscript 2 minus end superscript right square bracket end fraction عدد هذه الجمعية رجال كم يزيد عدد الرجال في الجمعية الأولى على عدد الرجال في الجمعية الثانية؟

أ. ٣

ب. ١٨

جـ. ٢٧

د. ٧٢