حلول الأسئلة
السؤال
أوجد القيمة الدقيقة لكل دالة مثلثية فيما يأتي:
الحل
0.5-
شاهد حلول جميع الاسئلة
حل أسئلة مراجعة تراكمية
أوجد القيمة الدقيقة لكل دالة مثلثية فيما يأتي:
43) format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2210.5%22%20y%3D%2218%22%3Esin%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2237.5%22%20y%3D%2218%22%3E210%3C%2Ftext%3E%3Ctext%20font-family%3D%22math13b2acfe2e38102074656ed938a%22%20font-size%3D%2212%22%20text-anchor%3D%22middle%22%20x%3D%2256.5%22%20y%3D%2212%22%3E%26%23x2218%3B%3C%2Ftext%3E%3C%2Fsvg%3E)
0.5-
44) format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2212.5%22%20y%3D%2226%22%3Ecos%3C%2Ftext%3E%3Cline%20stroke%3D%22%23000000%22%20stroke-linecap%3D%22square%22%20stroke-width%3D%221%22%20x1%3D%2231.5%22%20x2%3D%2243.5%22%20y1%3D%2220.5%22%20y2%3D%2220.5%22%2F%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2237.5%22%20y%3D%2215%22%3E3%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2237.5%22%20y%3D%2237%22%3E4%3C%2Ftext%3E%3Ctext%20font-family%3D%22math1437d7d1d97917cd627a34a6a0f%22%20font-size%3D%2216%22%20font-style%3D%22italic%22%20text-anchor%3D%22middle%22%20x%3D%2252.5%22%20y%3D%2226%22%3E%26%23x3C0%3B%3C%2Ftext%3E%3C%2Fsvg%3E)
45) format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2210.5%22%20y%3D%2218%22%3Ecot%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2234.5%22%20y%3D%2218%22%3E60%3C%2Ftext%3E%3Ctext%20font-family%3D%22math13b2acfe2e38102074656ed938a%22%20font-size%3D%2212%22%20text-anchor%3D%22middle%22%20x%3D%2248.5%22%20y%3D%2212%22%3E%26%23x2218%3B%3C%2Ftext%3E%3C%2Fsvg%3E)
في كل مما يأتي، أوجد زاويتين إحداهما بقياس موجب، والأخرى بقياس سالب، مشتركتين في ضلع الانتهاء مع كل زاوية معطاة:
46) format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2213.5%22%20y%3D%2216%22%3E125%3C%2Ftext%3E%3Ctext%20font-family%3D%22math138af86134b65d0f10fe33d30dd%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2231.5%22%20y%3D%2216%22%3E%26%23xB0%3B%3C%2Ftext%3E%3C%2Fsvg%3E)
47) format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Ctext%20font-family%3D%22math168513325172704765b2893ea86%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%226.5%22%20y%3D%2216%22%3E%26%23x2212%3B%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2222.5%22%20y%3D%2216%22%3E32%3C%2Ftext%3E%3Ctext%20font-family%3D%22math168513325172704765b2893ea86%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%2235.5%22%20y%3D%2216%22%3E%26%23xB0%3B%3C%2Ftext%3E%3C%2Fsvg%3E)
48) format('truetype')%3Bfont-weight%3Anormal%3Bfont-style%3Anormal%3B%7D%3C%2Fstyle%3E%3C%2Fdefs%3E%3Cline%20stroke%3D%22%23000000%22%20stroke-linecap%3D%22square%22%20stroke-width%3D%221%22%20x1%3D%222.5%22%20x2%3D%2214.5%22%20y1%3D%2220.5%22%20y2%3D%2220.5%22%2F%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%228.5%22%20y%3D%2215%22%3E2%3C%2Ftext%3E%3Ctext%20font-family%3D%22Arial%22%20font-size%3D%2216%22%20text-anchor%3D%22middle%22%20x%3D%228.5%22%20y%3D%2237%22%3E3%3C%2Ftext%3E%3Ctext%20font-family%3D%22math1437d7d1d97917cd627a34a6a0f%22%20font-size%3D%2216%22%20font-style%3D%22italic%22%20text-anchor%3D%22middle%22%20x%3D%2223.5%22%20y%3D%2226%22%3E%26%23x3C0%3B%3C%2Ftext%3E%3C%2Fsvg%3E)
أوجد مجموع كل من المتسلسلات الآتية (إن وجد):
49) ... + 36 + 48 + 64
256
50) ... + 48 + 63 + 27
لا يوجد.
51) 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لا يوجد.
إذا كانت
, y=1.5 , w=6, x=-4، فأوجد قيمة كل عبارة مما يأتي:
w2+y2- 6xz (52
56.25
x2+z2+5wz (53
wy+xz+w2-x2 (54
26